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Newbie Joined: 12 Feb 2004 Posts: 2

Greetings!

Trying to design an autoroller based on this output, where Luc = (x), the other 5 stats individually >= (y) and the sum of all stats >= {z}.

Attempted to simplify where Luc = (x) and the sum of all stats >= (y), but even that isn't working.

1) Str:10 Int: 9 Wis:10 Dex: 8 Con: 9 Luc: 9
2) Str:10 Int:10 Wis: 6 Dex: 9 Con: 7 Luc:11
3) Str: 9 Int:10 Wis: 8 Dex: 7 Con: 8 Luc:10
4) Str: 7 Int:10 Wis: 7 Dex: 9 Con:11 Luc:11
5) Str: 9 Int: 8 Wis:11 Dex: 9 Con:10 Luc: 6
1-5 chooses / Return rerolls:

Spent all day on this one, tried many structures to no avail. Any help at all would be hugely appreciated.

Cheers
TB

MASTER Joined: 28 Nov 2000 Posts: 4817 Location: USA

Are you sure you want Luc = x, not Luc >= x?
In your examples, two-digit numbers come immediately after the colon but one-digit numbers have a space in front of them. Since there aren't any good wildcards which match both spaces and digits, I used the fixed-width pattern.
I put the response after the fifth line instead of waiting for the MUD to ask. This will work on most MUDs.
You will need to add some extra spaces to make the pattern match the MUD output. There should be two spaces after each number, but the forum will only display one.
#VAR {x} {9}
#VAR {y} {8}
#VAR {z} {54}
#TR {1~) Str:(&2) Int:(&2) Wis:(&2) Dex:(&2) Con:(&2) Luc:(&2)} {#VAR answer 0;#IF ((%1 >= @y) AND (%2 >= @y) AND (%3 >= @y) AND (%4 >= @y) AND (%5 >= @y) AND (%6 = @x) AND ((%1 + %2 + %3 + %4 + %5 + %6) >= @z)) {#VAR answer 1}}
#COND {2~) Str:(&2) Int:(&2) Wis:(&2) Dex:(&2) Con:(&2) Luc:(&2)} {#IF ((%1 >= @y) AND (%2 >= @y) AND (%3 >= @y) AND (%4 >= @y) AND (%5 >= @y) AND (%6 = @x) AND ((%1 + %2 + %3 + %4 + %5 + %6) >= @z)) {#VAR answer 2}}
#COND {3~) Str:(&2) Int:(&2) Wis:(&2) Dex:(&2) Con:(&2) Luc:(&2)} {#IF ((%1 >= @y) AND (%2 >= @y) AND (%3 >= @y) AND (%4 >= @y) AND (%5 >= @y) AND (%6 = @x) AND ((%1 + %2 + %3 + %4 + %5 + %6) >= @z)) {#VAR answer 3}}
#COND {4~) Str:(&2) Int:(&2) Wis:(&2) Dex:(&2) Con:(&2) Luc:(&2)} {#IF ((%1 >= @y) AND (%2 >= @y) AND (%3 >= @y) AND (%4 >= @y) AND (%5 >= @y) AND (%6 = @x) AND ((%1 + %2 + %3 + %4 + %5 + %6) >= @z)) {#VAR answer 4}}
#COND {5~) Str:(&2) Int:(&2) Wis:(&2) Dex:(&2) Con:(&2) Luc:(&2)} {#IF ((%1 >= @y) AND (%2 >= @y) AND (%3 >= @y) AND (%4 >= @y) AND (%5 >= @y) AND (%6 = @x) AND ((%1 + %2 + %3 + %4 + %5 + %6) >= @z)) {#VAR answer 5};#IF (@answer > 0) {@answer} {#CR}}

Newbie Joined: 12 Feb 2004 Posts: 2

Greetings Lightbulb

Flawless code. Flexible too.. What can I say, this alone was worth the ZMUD registration. Thanks for the help!

Cheers
TB