Zugg Software :: View topic - ZMUD Regex # of matches or removing words

Novice Joined: 26 Dec 2002 Posts: 33 Location: USA

I want to remove multiple words matching the same pattern in a line, but I'm not sure if there's a way to know the # of times a #regex matched in a pattern. I know they get saved to %1..%99, but if I don't know how many there are...

Alternatively, if someone can think of an elegant way to do it, I'd be fine with that. Here's the scenario:

A room has an Exits line listing the available exits:
[Exits: north east south west up down other]

Each entry (north, east, etc) may either appear or not appear in the list, or may be enclosed in parentheses, e.g.:
[Exits: (north) south (west)]

The order will always be the same (NESWUDO), but that shouldn't matter since they're all matchable with %w or \a+.

The tricky part is that I want to remove any entries surrounded by parentheses, such that
[Exits: (north) south (west)]
becomes
[Exits: south]

Additionally, if there are no entries left ([Exits: ]), I'd like it to insert "none" ([Exits: none]).

Right now I'm accomplishing it by capturing the line, #gag'ing it, and #say'ing it with a %subregex(), but I'd much prefer being able to do it in-line or with a PSUB than having to rely on #gag/#show. Or any alternative solutions would also be welcomed..

Novice Joined: 26 Dec 2002 Posts: 33 Location: USA

So I went from scratch and started with this (ignoring Other exits because I really don't care about them for now):
(1) ^[Exits\:(?: north)?( $north$)?(?: east)?( $east$)?(?: south)?( $south$)?(?: west)?( $west$)?(?: up)?( $up$)?(?: down)?( $down$)?]

From that I tried to generalize down to:
(2) ^[Exits\:(?:(?: \a+)?( $\a+$)?)+]
except that it either matches too much (greedy) or too little (lazy).

For the sample line of:
[Exits: (north) east south (west)]
(1) will match %1=(north), %4=(west)
(2) will match %1=(west)

For (1) I have to manually do something silly like:
#IF (!%null(%1)) {#PSUB "" %x1}
#IF (!%null(%2)) {#PSUB "" %x2}
...
and (1) is also lame/inelegant. Ideally I'd like to manipulate (2) to match each instance AND have a way (with either (1) or (2)) to loop over the matches..

Novice Joined: 26 Dec 2002 Posts: 33 Location: USA

Alternative solution using #sub (it just struck me that #regex should be the way to do it, other than lousy zmud limitations...):
^(~[Exits~: *~])$ -> #SUB {%subregex(%1," $\a+$","")}

Posted: Wed Mar 12, 2008 6:50 am

This should do what you want, but you'll lose color information. For some reason PSUB and the Reparse option didn't play nice together.

#TRIGGER {(^~[Exits:*)( ~(%w~))(*~])} {#echo %1;#IF (!%null( %1)) {#SUB %1%3}} "" {reparse}

Novice Joined: 26 Dec 2002 Posts: 33 Location: USA

I don't lose color information because the whole line is the same color, so #sub preserves that. But..uh..wow, that's hax. Serious hax. I wasn't aware you could use the other trigger states for single-state triggers, that's not even hinted at in the Advanced Triggers page that I've read a billion times. Well played, at some point I was trying to figure out how to have the right number of reparse #cond's, but obviously this is the way to do it. Total hax.