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xiangwei
Beginner
Joined: 17 Apr 2004
Posts: 18
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 Posted: Mon Jun 04, 2007 11:31 am
help me thanks
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how do what list=2|3|2|3|4|4|5|2|5|5|6|7
#show xxx(2,@list) or xxx(@list,2)
Displays: 1|3|8
i dont know xxx=what?
pls tell me thanks |
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Tech
GURU
Joined: 18 Oct 2000
Posts: 2733
Location: Atlanta, USA
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Posted: Mon Jun 04, 2007 2:31 pm
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Your question was a little confusing at first but I think I understand what you mean. Unfortunately there is no single function that does what you want.
Your closest bet would be %ismember which will return the first one. Perhaps the easiest to simulate the behavior you want is with a #FORALL loop. Try this.
| Code: |
#VAR Count 0
#VAR test "2"
#FORALL @list {#ADD Count 1;#IF (@test =="%i") {#ADDITEM Found @Count }}
#SHOW @Found
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The code's untested but should work. Either way you get the general idea. |
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Asati di tempari! |
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xiangwei
Beginner
Joined: 17 Apr 2004
Posts: 18
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Posted: Mon Jun 04, 2007 11:12 pm
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Thank you, this is what I need
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